Twitters from Talygarn

Posting tweet...

Powered by Twitter Tools

Navigation:
Categories:
Archives:


Website From Only £70 Banner
Meta:

« « » »

Feeding Horses

Last week during our student theory lessons I was teaching feed including calculating feed rations for horses in different enviroments, some students were having a little difficulty working out feed rations so I found this piece on the internet which I thought maybe of interest.

The Impact of Cold Weather The following formula is used to calculate the increased DE (daily energy) requirement for a horse as a result of cold temperatures and wet, windy conditions: critical temperature – actual temperature = % increase in DE required.

Adjusting Energy Intake: An Example The following example clarifies how to adjust energy intake for a dry environmental temperature of 30°F with a wind chill that results in an actual temperature of 25°F. The example applies to a 1,100-pound horse at maintenance.

Step 1. Subtract the actual temperature (including the wind-chill adjustment) from the critical temperature (accounting for wet conditions if necessary): 45°F – 25°F = 20% increase in DE requirements.

Step 2. Because a 1,100-pound horse at maintenance requires 16.4 Mcal of DE per day and because the horse in this example requires a 20% increase in DE, you multiply as follows: 16.4 Mcal x 20% = +3.28 Mcal increase. The requirement thus increases as follows: 16.4 Mcal + 3.28 Mcal = 19.68 Mcal DE/day.

Step 3. Next you need to determine the amount of feed necessary to supply these increased calories. A 1,100-pound horse typically consumes 19 pounds of ration daily (1.7% of its body weight). Because the recommended DE level of the ration (concentrate mix plus forage) fed to a horse at maintenance is .90 Mcal DE/lb of feed, we can calculate the increase in feed as follows: 3.28 Mcal ÷ .90 Mcal = 3.64 pounds of additional feed to provide 19.68 Mcal DE/day.

Step 4. Determine the total amount of feed the horse requires by adding the 3.64 pounds of additional feed to the 19 pounds of feed the horse requires under normal conditions: 19.0 + 3.64 = 22.64 pounds per day of total ration.

Makes it all the clearer but I think I will stick to double the height and minus 5

Categorized as:College> Home> Horses
Posted on Monday, November 30th, 2009 at 1:56 am You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

Share This Blog Post With Others!

« Holidays   BHS Exams »

4 Comments »

  1. got it…lol

    Comment by sharon kingdom — December 2, 2009 @ 12:14 pm

  2. wow that is for a serious brainiac!!! hee hee!! xx

    Comment by freya — December 21, 2009 @ 7:52 am

  3. great advice thanks

    Comment by horse feed — December 23, 2009 @ 12:05 pm

  4. a bit complicated but ive written it all down thx

    horse feed

    Comment by horse feed — December 23, 2009 @ 12:06 pm

RSS feed for comments on this post. | TrackBack URI

Leave a comment

XHTML ( You can use these tags): <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <strike> <strong> .

Archive Tag Cloud
July 2010  June 2010  May 2010  April 2010  March 2010  February 2010  January 2010  December 2009  November 2009  October 2009  September 2009  August 2009  July 2009  June 2009  May 2009  April 2009  March 2009  February 2009  January 2009  December 2008  November 2008  October 2008  September 2008  August 2008  July 2008  June 2008  May 2008  April 2008  March 2008  February 2008  January 2008  December 2007  November 2007  October 2007  September 2007  August 2007 
Main Site Links

Riding Lessons

Riding Lessons

BHS/NVQ Training

BHS/NVQ Training

Pony Club

Pony Club

Competitions

Competitions

Gallery

Gallery

Horses/Ponies for sale

Horses/Ponies for sale

Website From Only £70 Banner